((1/x)-(1/5))/((1/x^2)-(1/25))

2 min read Jun 16, 2024
((1/x)-(1/5))/((1/x^2)-(1/25))

Simplifying the Expression: ((1/x)-(1/5))/((1/x^2)-(1/25))

This expression involves fractions within fractions, also known as complex fractions. To simplify it, we'll employ a few algebraic techniques.

1. Combining Fractions in the Numerator and Denominator

First, let's combine the fractions in the numerator and denominator separately.

Numerator:

  • Find a common denominator for (1/x) and (1/5), which is 5x.
  • ((1/x)-(1/5)) = (5/5x) - (x/5x) = (5-x)/5x

Denominator:

  • Find a common denominator for (1/x^2) and (1/25), which is 25x^2.
  • ((1/x^2)-(1/25)) = (25/25x^2) - (x^2/25x^2) = (25-x^2)/25x^2

2. Dividing by a Fraction

Now, our expression looks like this: ((5-x)/5x) / ((25-x^2)/25x^2)

Dividing by a fraction is the same as multiplying by its reciprocal. The reciprocal of ((25-x^2)/25x^2) is (25x^2/(25-x^2)).

Therefore:

((5-x)/5x) * (25x^2/(25-x^2))

3. Simplifying the Expression

  • Notice that (25-x^2) can be factored as (5+x)(5-x).
  • Cancel out the common factors (5-x) and 5x.

The final simplified expression is:

(5x)/(5+x)

Important Note: This simplification is valid as long as x ≠ 0 and x ≠ -5. These values would make the original expression undefined.

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