(1+5i)(4-2i)

2 min read Jun 16, 2024
(1+5i)(4-2i)

Multiplying Complex Numbers: (1+5i)(4-2i)

This article will explore the process of multiplying two complex numbers: (1 + 5i) and (4 - 2i). We'll delve into the steps involved and the resulting complex number.

Understanding Complex Numbers

A complex number is a number that can be expressed in the form a + bi, where 'a' and 'b' are real numbers, and 'i' is the imaginary unit defined as the square root of -1 (i.e., i² = -1).

Multiplication Process

  1. Distribution: We multiply each term of the first complex number by each term of the second complex number, similar to multiplying binomials.

    (1 + 5i)(4 - 2i) = (1 * 4) + (1 * -2i) + (5i * 4) + (5i * -2i)

  2. Simplifying: We perform the multiplication and simplify the terms.

    = 4 - 2i + 20i - 10i²

  3. Substituting i²: Remember that i² = -1. Substitute this into the equation.

    = 4 - 2i + 20i - 10(-1)

  4. Combining Real and Imaginary Terms: Combine the real terms and the imaginary terms separately.

    = (4 + 10) + (-2 + 20)i

  5. Final Result: The product of the two complex numbers is:

    = 14 + 18i

Therefore, (1 + 5i)(4 - 2i) = 14 + 18i.

Conclusion

Multiplying complex numbers involves applying the distributive property and simplifying the expression by substituting i² with -1. The result of this multiplication is another complex number, in this case, 14 + 18i.

Related Post


Featured Posts