(1-4m)(m^2-3m+8)=

2 min read Jun 16, 2024
(1-4m)(m^2-3m+8)=

Expanding the Expression: (1-4m)(m^2-3m+8)

This expression involves multiplying two binomials. We can use the distributive property (also known as FOIL) to expand it.

FOIL stands for:

  • First: Multiply the first terms of each binomial.
  • Outer: Multiply the outer terms of each binomial.
  • Inner: Multiply the inner terms of each binomial.
  • Last: Multiply the last terms of each binomial.

Let's apply this to our expression:

(1-4m)(m^2-3m+8)

1. First: 1 * m^2 = m^2

2. Outer: 1 * -3m = -3m

3. Inner: -4m * m^2 = -4m^3

4. Last: -4m * -3m = 12m^2

5. Last: -4m * 8 = -32m

Now, we combine the terms:

m^2 - 3m - 4m^3 + 12m^2 - 32m

Finally, we rearrange the terms in descending order of their exponents:

-4m^3 + 13m^2 - 35m

Therefore, the expanded form of (1-4m)(m^2-3m+8) is -4m^3 + 13m^2 - 35m.

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