(1-i)^3

3 min read Jun 16, 2024
(1-i)^3

Exploring the Power of Complex Numbers: (1-i)^3

This article delves into the intriguing world of complex numbers and explores the result of raising the complex number (1-i) to the power of 3. We will use basic complex number operations and the binomial theorem to arrive at our solution.

Understanding Complex Numbers

Complex numbers are numbers that can be expressed in the form a + bi, where a and b are real numbers, and i is the imaginary unit, defined as the square root of -1.

The complex number (1-i) can be visualized as a point on the complex plane, where the real part is 1 and the imaginary part is -1.

The Power of a Complex Number

To find (1-i)^3, we can use the binomial theorem which states:

**(a + b)^n = a^n + n*a^(n-1)b + (n(n-1)/2)a^(n-2)b^2 + ... + b^n

In our case, a = 1, b = -i, and n = 3. Substituting these values into the binomial theorem, we get:

(1-i)^3 = 1^3 + 31^2(-i) + 31(-i)^2 + (-i)^3

Simplifying this expression, we get:

(1-i)^3 = 1 - 3i - 3 + i

The Final Result

Combining the real and imaginary terms, we obtain the final answer:

**(1-i)^3 = ** -2 - 2i

Therefore, raising the complex number (1-i) to the power of 3 results in the complex number -2 - 2i.

Visualizing the Result

The result -2-2i can be visualized on the complex plane. It is located two units to the left of the origin and two units down. This shows that raising a complex number to a power can lead to a rotation and scaling of the corresponding point on the complex plane.

This exploration demonstrates the interesting properties of complex numbers and their powers. Understanding these properties is crucial in fields such as electrical engineering, quantum mechanics, and signal processing.

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