(2+7i)(2-7i) In A+bi Form

3 min read Jun 16, 2024
(2+7i)(2-7i) In A+bi Form

Expanding Complex Numbers: (2 + 7i)(2 - 7i)

This article explores the expansion of the complex number product (2 + 7i)(2 - 7i) into the standard a + bi form.

Understanding Complex Numbers

Complex numbers are numbers of the form a + bi, where a and b are real numbers and i is the imaginary unit, defined as √-1. The key property of i is that i² = -1.

Expanding the Product

To expand the product (2 + 7i)(2 - 7i), we can use the distributive property:

  1. Multiply each term in the first set of parentheses by each term in the second set: (2 + 7i)(2 - 7i) = 2(2 - 7i) + 7i(2 - 7i)

  2. Distribute: = 4 - 14i + 14i - 49i²

  3. Simplify using i² = -1: = 4 - 49(-1)

  4. Combine real and imaginary terms: = 4 + 49 = 53

Therefore, (2 + 7i)(2 - 7i) = 53.

The Result in a + bi Form

The result 53 can be expressed in the standard a + bi form as 53 + 0i. This shows that the product of a complex number and its conjugate is always a real number.

The Conjugate of a Complex Number

The conjugate of a complex number a + bi is a - bi. Notice that in our example, the two factors (2 + 7i) and (2 - 7i) are conjugates of each other.

Key Takeaways

  • The product of a complex number and its conjugate results in a real number.
  • Expanding complex products involves using the distributive property and simplifying using the definition of .
  • Any real number can be expressed in the complex form a + 0i.

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