(2i+3)x+(2-3i)y=5-i

3 min read Jun 16, 2024
(2i+3)x+(2-3i)y=5-i

Solving Complex Equations: A Step-by-Step Guide for (2i+3)x + (2-3i)y = 5-i

This article will guide you through solving the complex equation (2i+3)x + (2-3i)y = 5-i. We will break down the steps involved in finding the values of x and y that satisfy the equation.

Understanding Complex Equations

A complex equation involves complex numbers, which are numbers of the form a + bi, where 'a' and 'b' are real numbers, and 'i' is the imaginary unit (i² = -1). To solve a complex equation, we need to find the values of the unknown variables that make the equation true.

Solving the Equation

  1. Separate the Real and Imaginary Parts: Since the equation involves complex numbers, we need to separate the real and imaginary parts. We can do this by expanding the equation:

    (2i+3)x + (2-3i)y = 5-i

    (3x + 2y) + (2x - 3y)i = 5 - i

  2. Equate Real and Imaginary Parts: For the equation to be true, the real parts on both sides must be equal, and the imaginary parts must also be equal. This gives us two separate equations:

    • Real part: 3x + 2y = 5
    • Imaginary part: 2x - 3y = -1
  3. Solve the System of Equations: Now we have two linear equations with two unknowns. We can solve this system using various methods like substitution, elimination, or matrix methods.

    Using elimination:

    • Multiply the first equation by 3 and the second equation by 2 to make the coefficients of 'y' opposites:
      • 9x + 6y = 15
      • 4x - 6y = -2
    • Add the two equations together to eliminate 'y':
      • 13x = 13
    • Solve for 'x':
      • x = 1
    • Substitute the value of 'x' back into either of the original equations to solve for 'y':
      • 3(1) + 2y = 5
      • 2y = 2
      • y = 1

Solution

Therefore, the solution to the complex equation (2i+3)x + (2-3i)y = 5-i is:

  • x = 1
  • y = 1

This means that substituting these values into the original equation will make the equation true.

Related Post


Featured Posts