Dividing Polynomials: (2m³ + m² + m + 9) ÷ (2m - 1)
This article explores the process of dividing the polynomial (2m³ + m² + m + 9) by (2m - 1) using long division.
Step-by-Step Breakdown:
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Set up the long division:
___________ 2m-1 | 2m³ + m² + m + 9
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Divide the leading terms:
- Divide the leading term of the dividend (2m³) by the leading term of the divisor (2m). This gives you m².
- Write m² above the dividend.
- Multiply the divisor (2m - 1) by m². This gives you 2m³ - m².
- Subtract this result from the dividend:
m² 2m-1 | 2m³ + m² + m + 9 -(2m³ - m²) --------- 2m²
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Bring down the next term:
- Bring down the next term from the dividend (+ m):
m² 2m-1 | 2m³ + m² + m + 9 -(2m³ - m²) --------- 2m² + m
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Repeat the process:
- Divide the new leading term (2m²) by the leading term of the divisor (2m). This gives you m.
- Write m above the dividend.
- Multiply the divisor (2m - 1) by m. This gives you 2m² - m.
- Subtract this result from the previous result:
m² + m 2m-1 | 2m³ + m² + m + 9 -(2m³ - m²) --------- 2m² + m -(2m² - m) --------- 2m
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Bring down the next term:
- Bring down the next term from the dividend (+ 9):
m² + m 2m-1 | 2m³ + m² + m + 9 -(2m³ - m²) --------- 2m² + m -(2m² - m) --------- 2m + 9
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Repeat the process:
- Divide the new leading term (2m) by the leading term of the divisor (2m). This gives you 1.
- Write 1 above the dividend.
- Multiply the divisor (2m - 1) by 1. This gives you 2m - 1.
- Subtract this result from the previous result:
m² + m + 1 2m-1 | 2m³ + m² + m + 9 -(2m³ - m²) --------- 2m² + m -(2m² - m) --------- 2m + 9 -(2m - 1) --------- 10
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The remainder:
- The final result is 10, which is the remainder.
Conclusion:
Therefore, the division of (2m³ + m² + m + 9) by (2m - 1) results in:
(2m³ + m² + m + 9) ÷ (2m - 1) = m² + m + 1 + 10/(2m - 1)