(2n+1)+(2n+3)+(2n+5)+(2n+7)=-80

2 min read Jun 16, 2024
(2n+1)+(2n+3)+(2n+5)+(2n+7)=-80

Solving the Equation: (2n+1)+(2n+3)+(2n+5)+(2n+7) = -80

This article will guide you through the process of solving the equation (2n+1)+(2n+3)+(2n+5)+(2n+7) = -80. We'll break down each step to make it clear and understandable.

1. Simplifying the Equation

First, we need to simplify the left side of the equation by combining like terms:

  • (2n+1)+(2n+3)+(2n+5)+(2n+7) = -80
  • 8n + 16 = -80

2. Isolating the Variable (n)

To solve for 'n', we need to isolate it. We can do this by subtracting 16 from both sides of the equation:

  • 8n + 16 - 16 = -80 - 16
  • 8n = -96

3. Solving for 'n'

Finally, we solve for 'n' by dividing both sides of the equation by 8:

  • 8n / 8 = -96 / 8
  • n = -12

Conclusion

Therefore, the solution to the equation (2n+1)+(2n+3)+(2n+5)+(2n+7) = -80 is n = -12.

By following these simple steps, you can effectively solve equations like this one. Remember to always pay attention to combining like terms and isolating the variable to find the correct solution.

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