Dividing Polynomials: (2x^3 - 5x - 7) / (x - 2)
This article will explore the process of dividing the polynomial (2x^3 - 5x - 7) by the binomial (x - 2). We will use polynomial long division to accomplish this task.
Understanding Polynomial Long Division
Polynomial long division is similar to long division with numbers. We aim to find a quotient polynomial and a remainder that satisfy the equation:
Dividend = Divisor * Quotient + Remainder
In our case:
- Dividend: 2x^3 - 5x - 7
- Divisor: x - 2
Steps for Polynomial Long Division
-
Set up the division:
________ x - 2 | 2x^3 - 5x - 7
-
Focus on the leading terms: Divide the leading term of the dividend (2x^3) by the leading term of the divisor (x):
2x^2 ______ x - 2 | 2x^3 - 5x - 7
-
Multiply the quotient by the divisor: Multiply the quotient term (2x^2) by the entire divisor (x - 2):
2x^2 ______ x - 2 | 2x^3 - 5x - 7 2x^3 - 4x^2
-
Subtract: Subtract the result from the dividend:
2x^2 ______ x - 2 | 2x^3 - 5x - 7 2x^3 - 4x^2 ----------- 4x^2 - 5x
-
Bring down the next term: Bring down the next term from the dividend (-7):
2x^2 ______ x - 2 | 2x^3 - 5x - 7 2x^3 - 4x^2 ----------- 4x^2 - 5x - 7
-
Repeat steps 2-5: Now repeat the process with the new polynomial (4x^2 - 5x - 7):
- Divide the leading term (4x^2) by the leading term of the divisor (x): 4x
- Multiply 4x by (x - 2): 4x^2 - 8x
- Subtract:
2x^2 + 4x ______ x - 2 | 2x^3 - 5x - 7 2x^3 - 4x^2 ----------- 4x^2 - 5x - 7 4x^2 - 8x -------- 3x - 7
- Bring down the next term (-7)
-
Final step: Continue the process until the degree of the remainder is less than the degree of the divisor. In this case, we're left with:
2x^2 + 4x + 3 ______ x - 2 | 2x^3 - 5x - 7 2x^3 - 4x^2 ----------- 4x^2 - 5x - 7 4x^2 - 8x -------- 3x - 7 3x - 6 ---- -1
Result
Therefore, the division of (2x^3 - 5x - 7) by (x - 2) results in:
- Quotient: 2x^2 + 4x + 3
- Remainder: -1
We can express this as:
(2x^3 - 5x - 7) / (x - 2) = 2x^2 + 4x + 3 - (1/(x - 2))