(2x3 + X4 - 6x2 + 11x - 10) (x2 + 2 - X)

3 min read Jun 16, 2024
(2x3 + X4 - 6x2 + 11x - 10) (x2 + 2 - X)

Multiplying Polynomials: A Step-by-Step Guide

This article will walk you through the process of multiplying the following polynomials:

(2x³ + x⁴ - 6x² + 11x - 10) (x² + 2 - x)

We'll use the distributive property and a systematic approach to arrive at the final product.

Step 1: Organizing the terms

First, let's arrange both polynomials in descending order of their exponents:

(x⁴ + 2x³ - 6x² + 11x - 10) (x² - x + 2)

Step 2: Distributing each term

Now, we'll distribute each term of the first polynomial over the second polynomial. This means we'll multiply each term of the first polynomial by , then by -x, and finally by 2.

1. Multiplying by x²:

  • x⁴ * x² = x⁶
  • 2x³ * x² = 2x⁵
  • -6x² * x² = -6x⁴
  • 11x * x² = 11x³
  • -10 * x² = -10x²

2. Multiplying by -x:

  • x⁴ * -x = -x⁵
  • 2x³ * -x = -2x⁴
  • -6x² * -x = 6x³
  • 11x * -x = -11x²
  • -10 * -x = 10x

3. Multiplying by 2:

  • x⁴ * 2 = 2x⁴
  • 2x³ * 2 = 4x³
  • -6x² * 2 = -12x²
  • 11x * 2 = 22x
  • -10 * 2 = -20

Step 3: Combining like terms

We now have a list of terms. Let's combine the terms with the same exponents:

  • x⁶
  • 2x⁵ - x⁵ = x⁵
  • -6x⁴ - 2x⁴ + 2x⁴ = -6x⁴
  • 11x³ + 6x³ + 4x³ = 21x³
  • -10x² - 11x² - 12x² = -33x²
  • 10x + 22x = 32x
  • -20

Step 4: The Final Result

Combining all the terms, the final product of the two polynomials is:

(x⁴ + 2x³ - 6x² + 11x - 10) (x² - x + 2) = x⁶ + x⁵ - 6x⁴ + 21x³ - 33x² + 32x - 20

This process might seem lengthy, but with practice, you'll find multiplying polynomials becomes much easier!

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