(3i)(-3-4i)(7-5i)

2 min read Jun 16, 2024
(3i)(-3-4i)(7-5i)

Multiplying Complex Numbers: (3i)(-3-4i)(7-5i)

This article explores the multiplication of complex numbers, specifically focusing on the expression (3i)(-3-4i)(7-5i).

Understanding Complex Numbers

Complex numbers are numbers that can be expressed in the form a + bi, where a and b are real numbers and i is the imaginary unit, defined as the square root of -1 (i² = -1).

The Multiplication Process

To multiply complex numbers, we follow the distributive property, similar to multiplying binomials in algebra:

  1. Expand the product: (3i)(-3-4i)(7-5i) = (3i)(-21 + 15i - 28i + 20i²)

  2. Simplify using i² = -1: = (3i)(-21 - 13i - 20) = (3i)(-41 - 13i)

  3. Distribute again: = -123i - 39i²

  4. Substitute i² = -1 and simplify: = -123i + 39

  5. Express in standard form (a + bi): = 39 - 123i

Conclusion

Therefore, the product of (3i)(-3-4i)(7-5i) is 39 - 123i. This process highlights the importance of understanding the properties of complex numbers, particularly the value of i², to simplify expressions and arrive at the final complex number form.

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