Dividing Polynomials: (3x^4 - 2x^3 - x - 1) / (x^2 - 2x + 1)
In this article, we'll explore how to divide the polynomial (3x^4 - 2x^3 - x - 1) by (x^2 - 2x + 1). We'll employ polynomial long division, a method that mirrors the traditional long division you learned in elementary school.
Understanding the Steps
Let's break down the process step-by-step:
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Set up the Division: Arrange the polynomials in descending order of their exponents, filling in any missing terms with a coefficient of zero. We'll write the divisor (x^2 - 2x + 1) to the left and the dividend (3x^4 - 2x^3 - x - 1) to the right, separated by a division symbol.
x^2 - 2x + 1 | 3x^4 - 2x^3 + 0x^2 - x - 1
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Focus on the Leading Terms: Divide the leading term of the dividend (3x^4) by the leading term of the divisor (x^2). This gives us 3x^2. Write this term above the division symbol, aligning it with the x^2 term in the dividend.
3x^2 x^2 - 2x + 1 | 3x^4 - 2x^3 + 0x^2 - x - 1
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Multiply and Subtract: Multiply the divisor (x^2 - 2x + 1) by the term you just wrote (3x^2). This gives us 3x^4 - 6x^3 + 3x^2. Write this result below the dividend, aligning terms with their corresponding exponents. Subtract the entire expression from the dividend.
3x^2 x^2 - 2x + 1 | 3x^4 - 2x^3 + 0x^2 - x - 1 -(3x^4 - 6x^3 + 3x^2) --------------------- 4x^3 - 3x^2 - x
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Bring Down the Next Term: Bring down the next term of the dividend (-x).
3x^2 x^2 - 2x + 1 | 3x^4 - 2x^3 + 0x^2 - x - 1 -(3x^4 - 6x^3 + 3x^2) --------------------- 4x^3 - 3x^2 - x - 1
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Repeat Steps 2-4: Now, repeat the process. Divide the leading term of the new dividend (4x^3) by the leading term of the divisor (x^2), getting 4x. Write this term above the division symbol, aligning it with the x term in the dividend. Multiply the divisor by 4x, subtract, and bring down the next term (-1).
3x^2 + 4x x^2 - 2x + 1 | 3x^4 - 2x^3 + 0x^2 - x - 1 -(3x^4 - 6x^3 + 3x^2) --------------------- 4x^3 - 3x^2 - x - 1 -(4x^3 - 8x^2 + 4x) --------------------- 5x^2 - 5x - 1
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Final Step: Repeat the process one more time. Divide the leading term of the new dividend (5x^2) by the leading term of the divisor (x^2), getting 5. Multiply the divisor by 5, subtract, and you're left with a remainder of 9x - 6.
3x^2 + 4x + 5 x^2 - 2x + 1 | 3x^4 - 2x^3 + 0x^2 - x - 1 -(3x^4 - 6x^3 + 3x^2) --------------------- 4x^3 - 3x^2 - x - 1 -(4x^3 - 8x^2 + 4x) --------------------- 5x^2 - 5x - 1 -(5x^2 - 10x + 5) --------------------- 9x - 6
The Result
Therefore, the result of dividing (3x^4 - 2x^3 - x - 1) by (x^2 - 2x + 1) is:
(3x^4 - 2x^3 - x - 1) / (x^2 - 2x + 1) = 3x^2 + 4x + 5 + (9x - 6) / (x^2 - 2x + 1)
This can be expressed as the quotient 3x^2 + 4x + 5 with a remainder of 9x - 6.