(3x+1)/16+(2x-3)/7=(x+3)/8+(3x-1)/14

2 min read Jun 16, 2024
(3x+1)/16+(2x-3)/7=(x+3)/8+(3x-1)/14

Solving the Equation: (3x+1)/16 + (2x-3)/7 = (x+3)/8 + (3x-1)/14

This article will guide you through the process of solving the equation (3x+1)/16 + (2x-3)/7 = (x+3)/8 + (3x-1)/14.

1. Finding the Least Common Multiple (LCM)

To eliminate the fractions, we need to find the least common multiple of the denominators: 16, 7, 8, and 14. The LCM of these numbers is 112.

2. Multiplying Each Term by the LCM

Multiply each term of the equation by 112:

  • (112 * (3x+1)/16) + (112 * (2x-3)/7) = (112 * (x+3)/8) + (112 * (3x-1)/14)

This simplifies to:

  • 7(3x+1) + 16(2x-3) = 14(x+3) + 8(3x-1)

3. Expanding the Equation

Expand the equation by distributing:

  • 21x + 7 + 32x - 48 = 14x + 42 + 24x - 8

4. Combining Like Terms

Combine the terms with x and the constant terms:

  • 53x - 41 = 38x + 34

5. Isolating the Variable

Subtract 38x from both sides:

  • 15x - 41 = 34

Add 41 to both sides:

  • 15x = 75

6. Solving for x

Divide both sides by 15:

  • x = 5

Solution

Therefore, the solution to the equation (3x+1)/16 + (2x-3)/7 = (x+3)/8 + (3x-1)/14 is x = 5.

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