Solving the Equation: (3x-2)(2x-3) = (2x+5)(2x-1)
This article will guide you through the steps to solve the equation (3x-2)(2x-3) = (2x+5)(2x-1).
Expanding the Equation
First, we need to expand both sides of the equation using the FOIL method (First, Outer, Inner, Last):
- Left Side:
- (3x-2)(2x-3) = (3x * 2x) + (3x * -3) + (-2 * 2x) + (-2 * -3)
- = 6x² - 9x - 4x + 6
- = 6x² - 13x + 6
- Right Side:
- (2x+5)(2x-1) = (2x * 2x) + (2x * -1) + (5 * 2x) + (5 * -1)
- = 4x² - 2x + 10x - 5
- = 4x² + 8x - 5
Simplifying the Equation
Now, our equation looks like this: 6x² - 13x + 6 = 4x² + 8x - 5
To simplify, we need to move all terms to one side: 6x² - 13x + 6 - 4x² - 8x + 5 = 0
Combining like terms: 2x² - 21x + 11 = 0
Solving the Quadratic Equation
We now have a quadratic equation. There are several ways to solve it:
- Factoring: Attempt to factor the quadratic expression. If it can be factored, it will lead to two linear equations.
- Quadratic Formula: The most general approach, which always works:
- x = [-b ± √(b² - 4ac)] / 2a
- In our equation, a = 2, b = -21, and c = 11.
Let's use the quadratic formula:
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Substitute the values: x = [21 ± √((-21)² - 4 * 2 * 11)] / (2 * 2)
-
Simplify: x = [21 ± √(441 - 88)] / 4 x = [21 ± √353] / 4
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Calculate the two solutions: x1 = (21 + √353) / 4 x2 = (21 - √353) / 4
Solutions
Therefore, the solutions to the equation (3x-2)(2x-3) = (2x+5)(2x-1) are:
- x = (21 + √353) / 4
- x = (21 - √353) / 4