(3x-5)(2x-1)-(x+2)(6x-1)=0

Jasonbradley

2 min read

·

Jun 16, 2024

26

Share

Solving the Equation: (3x-5)(2x-1)-(x+2)(6x-1)=0

This article will guide you through the steps of solving the equation (3x-5)(2x-1)-(x+2)(6x-1)=0.

Step 1: Expand the Products

First, we need to expand the products on both sides of the equation:

• (3x-5)(2x-1) = 6x² - 3x - 10x + 5 = 6x² - 13x + 5
• (x+2)(6x-1) = 6x² - x + 12x - 2 = 6x² + 11x - 2

Now our equation becomes:

6x² - 13x + 5 - (6x² + 11x - 2) = 0

Step 2: Simplify the Equation

Next, we simplify the equation by distributing the negative sign and combining like terms:

6x² - 13x + 5 - 6x² - 11x + 2 = 0

-24x + 7 = 0

Step 3: Solve for x

Finally, we solve for x by isolating it:

• -24x = -7
• x = -7 / -24
• x = 7/24

Solution

Therefore, the solution to the equation (3x-5)(2x-1)-(x+2)(6x-1)=0 is x = 7/24.