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(3x−9)(2x−10) Express As A Trinomial

less than a minute read Jun 16, 2024
(3x−9)(2x−10) Express As A Trinomial

Expressing (3x−9)(2x−10) as a Trinomial

This problem involves expanding a product of two binomials, resulting in a trinomial. Here's how we do it:

Using the FOIL Method

The FOIL method is a mnemonic acronym for the order of operations when multiplying two binomials:

  • First: Multiply the first terms of each binomial.
  • Outer: Multiply the outer terms of the binomials.
  • Inner: Multiply the inner terms of the binomials.
  • Last: Multiply the last terms of each binomial.

Let's apply this to our problem:

(3x−9)(2x−10)

  • First: (3x)(2x) = 6x²
  • Outer: (3x)(-10) = -30x
  • Inner: (-9)(2x) = -18x
  • Last: (-9)(-10) = 90

Now, combine the like terms:

6x² - 30x - 18x + 90 = 6x² - 48x + 90

Therefore, (3x−9)(2x−10) expressed as a trinomial is 6x² - 48x + 90.

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