(4-2i)(3-3i)

2 min read Jun 16, 2024
(4-2i)(3-3i)

Multiplying Complex Numbers: (4-2i)(3-3i)

This article will guide you through the process of multiplying two complex numbers: (4-2i)(3-3i).

Understanding Complex Numbers

Complex numbers are numbers that can be expressed in the form a + bi, where a and b are real numbers, and i is the imaginary unit, defined as the square root of -1 (i² = -1).

Multiplying Complex Numbers

To multiply two complex numbers, we use the distributive property (also known as FOIL - First, Outer, Inner, Last) just like with binomials.

Step 1: Expand the expression

(4-2i)(3-3i) = 4(3-3i) -2i(3-3i)

Step 2: Distribute

= 12 - 12i - 6i + 6i²

Step 3: Simplify using i² = -1

= 12 - 12i - 6i - 6

Step 4: Combine real and imaginary terms

= (12-6) + (-12-6)i

Step 5: Final Result

= 6 - 18i

Therefore, the product of (4-2i) and (3-3i) is 6 - 18i.

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