Solving Complex Equation: (4-3i)x(2+5i)y = 6-11i
This article explores how to solve the complex equation (4-3i)x(2+5i)y = 6-11i for the unknown variables x and y.
Understanding Complex Numbers
Complex numbers are numbers of the form a + bi, where a and b are real numbers and i is the imaginary unit, defined as the square root of -1.
Solving the Equation
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Expand the left side:
The first step is to expand the left side of the equation by multiplying the complex numbers:
(4-3i)x(2+5i)y = (8 + 20i - 6i - 15i²)xy = (8 + 14i + 15)xy = (23 + 14i)xy
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Equate Real and Imaginary Parts:
Since the equation is an equality between complex numbers, the real and imaginary parts on both sides must be equal. We can write this as:
- Real part: 23xy = 6
- Imaginary part: 14xy = -11
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Solve for x and y:
We now have a system of two equations with two unknowns. We can solve for x and y using various methods like substitution or elimination.
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Using Elimination:
- Multiply the first equation by -14 and the second equation by 23: -322xy = -84 322xy = -253
- Adding these equations gives: 0 = -337, which is a contradiction.
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Using Substitution:
- Solve the first equation for xy: xy = 6/23
- Substitute this value of xy into the second equation: 14(6/23) = -11
- This leads to 84/23 = -11, which is again a contradiction.
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Conclusion
The contradiction obtained from both methods indicates that there is no solution to the equation (4-3i)x(2+5i)y = 6-11i for the real variables x and y. This means no pair of real numbers x and y can satisfy the given equation.