(4x^2-100)÷6(x+5)

2 min read Jun 16, 2024
(4x^2-100)÷6(x+5)

Simplifying the Expression (4x² - 100) ÷ 6(x+5)

This expression represents a division of two algebraic expressions:

  • Dividend: (4x² - 100)
  • Divisor: 6(x+5)

To simplify this expression, we can follow these steps:

1. Factor the Dividend

The dividend (4x² - 100) is a difference of squares. We can factor it as:

(4x² - 100) = (2x + 10)(2x - 10)

2. Simplify the Divisor

The divisor 6(x+5) can be left as it is.

3. Rewrite the Expression

Now we can rewrite the original expression as:

[(2x + 10)(2x - 10)] ÷ 6(x+5)

4. Cancel Common Factors

Notice that both the dividend and divisor have a common factor of (2x + 10):

  • Dividend: (2x + 10)(2x - 10)
  • Divisor: 6**(2x + 10)**

We can cancel this common factor:

(2x - 10) ÷ 6

5. Final Simplification

The final simplified form of the expression is:

(x - 5) ÷ 3

Therefore, the simplified form of (4x² - 100) ÷ 6(x+5) is (x - 5) ÷ 3.

Important Note: This simplification is valid only when x ≠ -5, because the original expression is undefined for x = -5 due to division by zero.

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