(4x3 + 5)(2x3 + 3) = 8x6 + Tx3 + 15

2 min read Jun 16, 2024
(4x3 + 5)(2x3 + 3) = 8x6 + Tx3 + 15

Solving for the Unknown Coefficient 't'

This article will guide you through the process of finding the value of the unknown coefficient 't' in the equation:

(4x³ + 5)(2x³ + 3) = 8x⁶ + tx³ + 15

Expanding the Left-Hand Side

The first step is to expand the left-hand side of the equation using the distributive property (also known as FOIL - First, Outer, Inner, Last):

(4x³ + 5)(2x³ + 3) = (4x³ * 2x³) + (4x³ * 3) + (5 * 2x³) + (5 * 3)

Simplifying the terms:

(4x³ + 5)(2x³ + 3) = 8x⁶ + 12x³ + 10x³ + 15

Combining like terms:

(4x³ + 5)(2x³ + 3) = 8x⁶ + 22x³ + 15

Comparing Coefficients

Now we can compare the expanded left-hand side with the right-hand side of the original equation:

8x⁶ + 22x³ + 15 = 8x⁶ + tx³ + 15

We can see that the coefficients of the x⁶ and constant terms match. The only difference is in the coefficient of the x³ term.

Therefore, we can conclude:

t = 22

Conclusion

We have successfully solved for the unknown coefficient 't' in the equation:

(4x³ + 5)(2x³ + 3) = 8x⁶ + tx³ + 15

The value of 't' is 22.

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