(5-2i)(2+7i)

2 min read Jun 16, 2024
(5-2i)(2+7i)

Multiplying Complex Numbers: (5-2i)(2+7i)

This article will guide you through the multiplication of complex numbers, specifically the product of (5-2i) and (2+7i).

Understanding Complex Numbers

Complex numbers are expressed in the form a + bi, where 'a' and 'b' are real numbers, and 'i' is the imaginary unit, defined as the square root of -1 (i² = -1).

The Multiplication Process

To multiply complex numbers, we use the distributive property, similar to multiplying binomials:

  1. FOIL Method: "First, Outer, Inner, Last"

    • First: (5)(2) = 10
    • Outer: (5)(7i) = 35i
    • Inner: (-2i)(2) = -4i
    • Last: (-2i)(7i) = -14i²
  2. Simplify: Remember that i² = -1, so we substitute:

    • 10 + 35i - 4i - 14(-1)
  3. Combine Real and Imaginary Terms:

    • (10 + 14) + (35 - 4)i
  4. Final Result:

    • 24 + 31i

Therefore, the product of (5-2i) and (2+7i) is 24 + 31i.

Key Points

  • Complex Multiplication: The product of two complex numbers is also a complex number.
  • FOIL Method: This method ensures that all terms are multiplied.
  • Simplifying with i²: Remember to substitute i² with -1.

By following these steps, you can confidently multiply complex numbers and arrive at the correct answer.

Related Post


Featured Posts