(8i)(4i)(-9i)

2 min read Jun 16, 2024
(8i)(4i)(-9i)

Simplifying Complex Number Multiplication

This article will explore the simplification of the complex number multiplication problem: (8i)(4i)(-9i).

Understanding Complex Numbers

Complex numbers are numbers that can be expressed in the form a + bi, where a and b are real numbers, and i is the imaginary unit, defined as the square root of -1.

Multiplication of Complex Numbers

When multiplying complex numbers, we distribute like any other binomial multiplication. However, we must remember that i² = -1.

Solving the Problem

Let's break down the problem step-by-step:

  1. Multiply the first two terms: (8i)(4i) = 32i²

  2. Substitute i² with -1: 32i² = 32(-1) = -32

  3. Multiply the result by the third term: -32(-9i) = 288i

Therefore, (8i)(4i)(-9i) = 288i.

Conclusion

This example demonstrates the process of multiplying complex numbers. The key is to remember the value of i² and perform the multiplication as you would with any other binomial expression. The final result is a purely imaginary number.

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