Long Division of Polynomials: (8x^3 - 3x + 1) / (4x^3 + x^2 - 2x - 3)
Long division of polynomials is a method for dividing one polynomial by another polynomial. It is similar to the long division of numbers. In this article, we will explore how to divide the polynomial (8x^3 - 3x + 1) by (4x^3 + x^2 - 2x - 3).
Setting up the Division
- Arrange the polynomials in descending order of their exponents. In our case, both polynomials are already arranged.
- Write the dividend (8x^3 - 3x + 1) under the division symbol and the divisor (4x^3 + x^2 - 2x - 3) outside the symbol.
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4x^3 + x^2 - 2x - 3 | 8x^3 - 3x + 1
Performing the Division
- Divide the leading term of the dividend (8x^3) by the leading term of the divisor (4x^3). This gives us 2. Write this quotient above the dividend.
- Multiply the quotient (2) by the entire divisor (4x^3 + x^2 - 2x - 3). This gives us 8x^3 + 2x^2 - 4x - 6. Write this result below the dividend.
- Subtract the result from the dividend.
- Bring down the next term of the dividend (1).
2
4x^3 + x^2 - 2x - 3 | 8x^3 - 3x + 1
-(8x^3 + 2x^2 - 4x - 6)
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-2x^2 + x + 7
- Repeat steps 1-4 with the new dividend (-2x^2 + x + 7).
- Divide the leading term of the new dividend (-2x^2) by the leading term of the divisor (4x^3). This gives us -1/2x.
- Multiply the new quotient (-1/2x) by the divisor. This gives us -2x^2 - 1/2x + x + 3/2.
- Subtract this result from the current dividend.
- Bring down the next term (which is 0, since the original dividend didn't have an x^2 term).
2 - 1/2x
4x^3 + x^2 - 2x - 3 | 8x^3 - 3x + 1
-(8x^3 + 2x^2 - 4x - 6)
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-2x^2 + x + 7
-(-2x^2 - 1/2x + x + 3/2)
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3/2x + 11/2
- Continue this process until the degree of the remaining dividend is less than the degree of the divisor. In this case, the degree of (3/2x + 11/2) is 1, which is less than the degree of (4x^3 + x^2 - 2x - 3). Therefore, we stop here.
The Result
The result of the long division is:
(8x^3 - 3x + 1) / (4x^3 + x^2 - 2x - 3) = 2 - 1/2x + (3/2x + 11/2) / (4x^3 + x^2 - 2x - 3)
This can also be written as:
(8x^3 - 3x + 1) = (4x^3 + x^2 - 2x - 3)(2 - 1/2x) + (3/2x + 11/2)
This indicates that the original polynomial (8x^3 - 3x + 1) can be expressed as the product of the divisor (4x^3 + x^2 - 2x - 3) and the quotient (2 - 1/2x) plus the remainder (3/2x + 11/2).