(ab-3/2cd)(2ab+3cd)

Jasonbradley

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Jun 16, 2024

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Multiplying Binomials: (ab - 3/2cd)(2ab + 3cd)

This article will guide you through the process of multiplying the binomials (ab - 3/2cd)(2ab + 3cd). We will use the FOIL method to expand this expression.

FOIL stands for:

• First: Multiply the first terms of each binomial.
• Outer: Multiply the outer terms of the binomials.
• Inner: Multiply the inner terms of the binomials.
• Last: Multiply the last terms of each binomial.

Let's apply FOIL to our expression:

(ab - 3/2cd)(2ab + 3cd)

• F: (ab)(2ab) = 2a²b²
• O: (ab)(3cd) = 3abcd
• I: (-3/2cd)(2ab) = -3abcd
• L: (-3/2cd)(3cd) = -9/2c²d²

Now, combine the terms:

2a²b² + 3abcd - 3abcd - 9/2c²d²

Simplify by combining like terms:

2a²b² - 9/2c²d²

Therefore, the product of (ab - 3/2cd)(2ab + 3cd) is 2a²b² - 9/2c²d².