Finding the Derivative of cos^(-1)((4x^(3))/(64)-(3)/(4)x)
This article will walk you through the steps involved in finding the derivative of the inverse cosine function with a complex argument:
cos^(-1)((4x^(3))/(64)-(3)/(4)x)
We will use the chain rule and the derivative of the inverse cosine function to achieve this.
Understanding the Chain Rule
The chain rule is a fundamental concept in calculus that helps us differentiate composite functions. It states that the derivative of a composite function is equal to the product of the derivative of the outer function and the derivative of the inner function.
In mathematical terms:
If y = f(u) and u = g(x), then the derivative of y with respect to x is:
dy/dx = (dy/du) * (du/dx)
Finding the Derivative
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Identify the inner and outer functions:
- Our outer function is f(u) = cos^(-1)(u)
- Our inner function is u = g(x) = (4x^(3))/(64)-(3)/(4)x
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Find the derivatives of the inner and outer functions:
- d(f(u))/du = -1/√(1 - u^2) (The derivative of the inverse cosine function)
- d(g(x))/dx = (12x^2)/64 - 3/4 = (3x^2)/16 - 3/4 (Using the power rule)
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Apply the Chain Rule:
- d(cos^(-1)((4x^(3))/(64)-(3)/(4)x))/dx = -1/√(1 - ((4x^(3))/(64)-(3)/(4)x)^2) * ((3x^2)/16 - 3/4)
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Simplify the expression:
- d(cos^(-1)((4x^(3))/(64)-(3)/(4)x))/dx = -((3x^2)/16 - 3/4) / √(1 - ( (4x^3)/64 - (3/4)x )^2)
Conclusion
The derivative of cos^(-1)((4x^(3))/(64)-(3)/(4)x) is:
-((3x^2)/16 - 3/4) / √(1 - ( (4x^3)/64 - (3/4)x )^2)
This result can be further simplified or manipulated depending on the context of the problem.