## Factoring the Expression (p² + p - 6)(p² - 6)

This expression involves two quadratic factors. Let's break down how to factor it completely.

### Factoring the First Quadratic

The first factor, **(p² + p - 6)**, is a quadratic trinomial that can be factored using the following steps:

**Find two numbers that multiply to -6 and add up to 1.**These numbers are 3 and -2.**Rewrite the middle term (p) using these numbers:**(p² + 3p - 2p - 6)**Factor by grouping:**p(p + 3) - 2(p + 3)**Factor out the common factor (p + 3):**(p + 3)(p - 2)

Therefore, (p² + p - 6) factors to **(p + 3)(p - 2)**.

### Factoring the Second Quadratic

The second factor, **(p² - 6)**, is a difference of squares. We can factor it using the following pattern:

**a² - b² = (a + b)(a - b)**

In this case, a = p and b = √6. So, the factored form is:

**(p + √6)(p - √6)**

### Final Factored Form

Combining the factored forms of both quadratic factors, we get the completely factored expression:

**(p + 3)(p - 2)(p + √6)(p - √6)**

This is the final factored form of (p² + p - 6)(p² - 6).