(sqrt 3)^2*(-8i)^2

less than a minute read Jun 16, 2024
(sqrt 3)^2*(-8i)^2

Simplifying $(\sqrt{3})^2 \cdot (-8i)^2$

This expression involves simplifying powers of imaginary numbers and radicals. Here's a step-by-step solution:

1. Simplifying the radicals:

  • $(\sqrt{3})^2 = 3$ (The square of a square root cancels out)

2. Simplifying the imaginary powers:

  • (-8i)² = (-8)² * (i)² = 64 * (-1) = -64
    • Remember that i² = -1

3. Multiplying the results:

  • 3 * (-64) = -192

Therefore, the simplified form of $(\sqrt{3})^2 \cdot (-8i)^2$ is -192.

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