## Solving the Equation (x+10)(x-10) = 300

This problem involves solving a quadratic equation. Here's how to approach it step-by-step:

**1. Expand the Left Side**

The left side of the equation is a product of two binomials. We can expand it using the **FOIL** method (First, Outer, Inner, Last):

(x + 10)(x - 10) = x² - 10x + 10x - 100 = x² - 100

**2. Simplify the Equation**

Now the equation looks like this:

x² - 100 = 300

**3. Move Constant Term to the Right Side**

Add 100 to both sides of the equation:

x² = 400

**4. Take the Square Root of Both Sides**

Remember that when taking the square root, we need to consider both positive and negative solutions:

x = ±√400

**5. Calculate the Solutions**

√400 = 20, so the solutions are:

x = 20 or x = -20

**Therefore, the solutions to the equation (x+10)(x-10) = 300 are x = 20 and x = -20.**