(x+2)^2/2x-3-1=x^2+10/2x-3

2 min read Jun 16, 2024
(x+2)^2/2x-3-1=x^2+10/2x-3

Solving the Equation: (x+2)^2 / (2x-3) - 1 = (x^2+10) / (2x-3)

This article will guide you through the steps of solving the equation:

(x+2)^2 / (2x-3) - 1 = (x^2+10) / (2x-3)

1. Simplifying the Equation

To begin, we need to simplify the equation. Let's combine the terms on the left side:

(x+2)^2 / (2x-3) - (2x-3) / (2x-3) = (x^2+10) / (2x-3)

Now, we can combine the numerators on the left side:

[(x+2)^2 - (2x-3)] / (2x-3) = (x^2+10) / (2x-3)

2. Expanding and Combining Terms

Next, we expand the square on the left side:

(x^2 + 4x + 4 - 2x + 3) / (2x-3) = (x^2+10) / (2x-3)

Combining like terms, we get:

(x^2 + 2x + 7) / (2x-3) = (x^2+10) / (2x-3)

3. Eliminating the Denominators

Since both sides of the equation have the same denominator, we can multiply both sides by (2x-3) to eliminate the denominators:

(x^2 + 2x + 7) = (x^2 + 10)

4. Solving for x

Now, we can solve for x by simplifying the equation further:

2x + 7 = 10

2x = 3

x = 3/2

Conclusion

Therefore, the solution to the equation (x+2)^2 / (2x-3) - 1 = (x^2+10) / (2x-3) is x = 3/2.

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