Jasonbradley
Home

(x+2)(x^2-2x+4)-x(x^2-5)=15

2 min read Jun 16, 2024
(x+2)(x^2-2x+4)-x(x^2-5)=15

Solving the Equation (x+2)(x^2-2x+4)-x(x^2-5)=15

This article will guide you through the steps of solving the given equation: (x+2)(x^2-2x+4)-x(x^2-5)=15.

1. Expanding the Equation

First, we need to expand the equation by multiplying the terms:

  • (x+2)(x^2-2x+4): This is a special product called the sum of cubes. It can be expanded directly as: x^3 + 2^3 = x^3 + 8
  • x(x^2-5): This simplifies to x^3 - 5x

Now our equation looks like this: x^3 + 8 - x^3 + 5x = 15

2. Simplifying the Equation

Combining like terms, we get: 5x + 8 = 15

3. Isolate the Variable

To isolate the variable 'x', we need to subtract 8 from both sides: 5x = 7

4. Solving for 'x'

Finally, divide both sides by 5 to get the value of x: x = 7/5

Therefore, the solution to the equation (x+2)(x^2-2x+4)-x(x^2-5)=15 is x = 7/5.

Related Post

Featured Posts