(x%2B4)%3D0-values-of-a-b-and-c.jpeg "(x+3)(x+4)=0 Values Of A B And C")
Solving for a, b, and c in (x+3)(x+4)=0
The equation (x+3)(x+4)=0 represents a quadratic equation in standard form: ax² + bx + c = 0. To find the values of a, b, and c, we need to expand the equation and then compare it to the standard form.
Expanding the Equation
Let's expand the equation (x+3)(x+4) using the FOIL method:
- First: x * x = x²
- Outer: x * 4 = 4x
- Inner: 3 * x = 3x
- Last: 3 * 4 = 12
Combining the terms, we get: x² + 4x + 3x + 12 = 0
Simplifying: x² + 7x + 12 = 0
Identifying a, b, and c
Now, we can clearly see the values of a, b, and c:
- a = 1 (coefficient of x²)
- b = 7 (coefficient of x)
- c = 12 (constant term)
Therefore, the values of a, b, and c for the quadratic equation (x+3)(x+4)=0 are a = 1, b = 7, and c = 12.