Expanding (x+3)(x-5) to Standard Form
In mathematics, the standard form of a quadratic equation is expressed as ax² + bx + c, where a, b, and c are constants and a ≠ 0. To express the given expression (x+3)(x-5) in standard form, we need to expand and simplify it.
Expanding the Expression
We can use the FOIL method to expand the expression:
- First: x * x = x²
- Outer: x * -5 = -5x
- Inner: 3 * x = 3x
- Last: 3 * -5 = -15
Combining the terms, we get:
(x+3)(x-5) = x² - 5x + 3x - 15
Simplifying the Expression
Now we can combine the like terms:
x² - 5x + 3x - 15 = x² - 2x - 15
Final Answer
Therefore, the standard form of (x+3)(x-5) is x² - 2x - 15.