(x+4)^2-25=0

2 min read Jun 16, 2024
(x+4)^2-25=0

Solving the Equation: (x+4)^2 - 25 = 0

This equation is a quadratic equation in disguise. We can solve it using a few simple steps:

1. Simplify using the difference of squares pattern:

The expression on the left-hand side of the equation is in the form of a difference of squares: (a^2 - b^2), where a = x+4 and b = 5. We can factor this using the formula: (a + b)(a - b).

Applying this to our equation:

(x + 4 + 5)(x + 4 - 5) = 0

2. Simplify the expression:

(x + 9)(x - 1) = 0

3. Apply the Zero Product Property:

The Zero Product Property states that if the product of two factors is zero, then at least one of the factors must be zero.

Therefore, either:

  • x + 9 = 0 or
  • x - 1 = 0

4. Solve for x:

  • x + 9 = 0 --> x = -9
  • x - 1 = 0 --> x = 1

Therefore, the solutions to the equation (x+4)^2 - 25 = 0 are x = -9 and x = 1.

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