(x+4)(x^2-4x+16)-x(x-5)(x+5)=264

2 min read Jun 16, 2024
(x+4)(x^2-4x+16)-x(x-5)(x+5)=264

Solving the Equation: (x+4)(x^2-4x+16)-x(x-5)(x+5)=264

This article will guide you through solving the algebraic equation: (x+4)(x^2-4x+16)-x(x-5)(x+5)=264. We'll break down the steps involved in simplifying the equation and ultimately finding the solution(s) for x.

Expanding and Simplifying the Equation

  1. Expand the first set of parentheses:

    The expression (x+4)(x^2-4x+16) represents the expansion of a sum of cubes. We can use the formula: (a+b)(a^2-ab+b^2) = a^3 + b^3.

    Therefore, (x+4)(x^2-4x+16) = x^3 + 4^3 = x^3 + 64

  2. Expand the second set of parentheses:

    The expression x(x-5)(x+5) involves the difference of squares formula: (a-b)(a+b) = a^2 - b^2.

    Therefore, x(x-5)(x+5) = x(x^2 - 25) = x^3 - 25x

  3. Substitute the expanded expressions back into the original equation:

    The equation now becomes: x^3 + 64 - (x^3 - 25x) = 264

  4. Simplify by distributing the negative sign:

    x^3 + 64 - x^3 + 25x = 264

  5. Combine like terms:

    25x + 64 = 264

Solving for x

  1. Isolate the x term:

    25x = 200

  2. Divide both sides by 25:

    x = 8

Solution

The solution to the equation (x+4)(x^2-4x+16)-x(x-5)(x+5)=264 is x = 8.

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