(x^2-2x)(2 X-2)-9(2x-2)/(x^2-2x) =0

Jasonbradley

4 min read

·

Jun 17, 2024

35

Share

Solving the Equation: (x^2 - 2x)(2x - 2) - 9(2x - 2) / (x^2 - 2x) = 0

This equation presents a challenge due to its complex structure and the presence of fractions. Let's break down the steps to find the solution:

1. Factoring and Simplifying

• Factor out (2x - 2): Notice that (2x - 2) appears in both terms of the numerator. Factoring it out simplifies the expression: (2x - 2) [(x^2 - 2x) - 9 / (x^2 - 2x)] = 0
• Simplify the bracketed term: To combine the terms within the brackets, we need a common denominator. The common denominator is (x^2 - 2x): (2x - 2) [(x^2 - 2x)^2 - 9] / (x^2 - 2x) = 0
• Further simplification: Now, we can simplify the numerator: (2x - 2) [(x^2 - 2x + 3)(x^2 - 2x - 3)] / (x^2 - 2x) = 0

2. Identifying Potential Solutions

• Zero Product Property: The product of two factors is zero if and only if at least one of the factors is zero. We can apply this property to our equation:
  • 2x - 2 = 0
  • x^2 - 2x + 3 = 0
  • x^2 - 2x - 3 = 0
  • x^2 - 2x = 0

3. Solving for x

• Solve for x in 2x - 2 = 0:
  • 2x = 2
  • x = 1
• Solve for x in x^2 - 2x + 3 = 0:
  • This quadratic equation does not factor easily. We can use the quadratic formula:
    • x = [-b ± √(b^2 - 4ac)] / 2a
    • In this case, a = 1, b = -2, and c = 3.
    • x = [2 ± √((-2)^2 - 4 * 1 * 3)] / 2 * 1
    • x = [2 ± √(-8)] / 2
    • x = 1 ± i√2 (where 'i' is the imaginary unit)
• Solve for x in x^2 - 2x - 3 = 0:
  • This quadratic equation factors:
    • (x - 3)(x + 1) = 0
    • x = 3 or x = -1
• Solve for x in x^2 - 2x = 0:
  • Factor out x:
    • x(x - 2) = 0
    • x = 0 or x = 2

4. Checking for Extraneous Solutions

It's important to check if any of the potential solutions make the denominator (x^2 - 2x) equal to zero, as this would make the original equation undefined.

• x = 0 and x = 2 make the denominator zero. Therefore, these solutions are extraneous and must be discarded.

5. Final Solutions

The solutions to the equation (x^2 - 2x)(2x - 2) - 9(2x - 2) / (x^2 - 2x) = 0 are:

• x = 1
• x = 1 + i√2
• x = 1 - i√2
• x = 3
• x = -1