Solving the Equation (x+10)(x-10) = 300
This equation presents a quadratic equation in disguise, and we can solve it by following these steps:
1. Expanding the Equation
First, we need to expand the left side of the equation using the difference of squares pattern: (x + 10)(x - 10) = x² - 10² = x² - 100
This gives us the simplified equation: x² - 100 = 300
2. Rearranging the Equation
Now, we move the constant term to the right side of the equation: x² = 300 + 100
This simplifies to: x² = 400
3. Solving for x
To isolate x, we take the square root of both sides: √x² = ±√400
This gives us two possible solutions: x = ±20
Therefore, the solutions to the equation (x+10)(x-10) = 300 are x = 20 and x = -20.
Verification
We can verify our solutions by plugging them back into the original equation:
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For x = 20: (20 + 10)(20 - 10) = 30 * 10 = 300
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For x = -20: (-20 + 10)(-20 - 10) = (-10) * (-30) = 300
Both solutions satisfy the original equation, confirming our results.