(x+10)(x-10)=300 Find X

2 min read Jun 16, 2024

Solving the Equation (x+10)(x-10) = 300

This problem involves solving a quadratic equation. Here's how to approach it step-by-step:

1. Expand the Left Side

The left side of the equation is a product of two binomials. We can expand it using the FOIL method (First, Outer, Inner, Last):

(x + 10)(x - 10) = x² - 10x + 10x - 100 = x² - 100

2. Simplify the Equation

Now the equation looks like this:

x² - 100 = 300

3. Move Constant Term to the Right Side

Add 100 to both sides of the equation:

x² = 400

4. Take the Square Root of Both Sides

Remember that when taking the square root, we need to consider both positive and negative solutions:

x = ±√400

5. Calculate the Solutions

√400 = 20, so the solutions are:

x = 20 or x = -20

Therefore, the solutions to the equation (x+10)(x-10) = 300 are x = 20 and x = -20.