(x+3)(x-1)=5

2 min read Jun 16, 2024
(x+3)(x-1)=5

Solving the Quadratic Equation: (x+3)(x-1) = 5

This article will guide you through the steps of solving the quadratic equation (x+3)(x-1) = 5.

Expanding the Equation

First, we need to expand the left side of the equation by multiplying the terms:

(x+3)(x-1) = x² + 2x - 3

Now, the equation looks like this:

x² + 2x - 3 = 5

Setting the Equation to Zero

To solve for x, we need to set the equation to zero:

x² + 2x - 3 - 5 = 0

Which simplifies to:

x² + 2x - 8 = 0

Factoring the Quadratic Equation

Now we can factor the quadratic equation:

(x+4)(x-2) = 0

Solving for x

For the product of two terms to be zero, at least one of them must be zero. Therefore, we have two possible solutions:

  • x + 4 = 0 => x = -4
  • x - 2 = 0 => x = 2

The Solutions

Therefore, the solutions to the quadratic equation (x+3)(x-1) = 5 are x = -4 and x = 2.

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