Solving the Equation: (x-1)^3 - x(x+1)^2 = 5x(2-x) - 11(x+2)
This article will guide you through the process of solving the equation (x-1)^3 - x(x+1)^2 = 5x(2-x) - 11(x+2). We will break down each step, making it easy to follow.
Expanding the Equation
First, we need to expand the equation to get rid of the parentheses and simplify it.
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Expanding the cubes and squares:
- (x-1)^3 = (x-1)(x-1)(x-1) = x^3 - 3x^2 + 3x - 1
- x(x+1)^2 = x(x+1)(x+1) = x(x^2 + 2x + 1) = x^3 + 2x^2 + x
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Expanding the remaining products:
- 5x(2-x) = 10x - 5x^2
- -11(x+2) = -11x - 22
Now, our equation becomes: x^3 - 3x^2 + 3x - 1 - (x^3 + 2x^2 + x) = 10x - 5x^2 - 11x - 22
Simplifying the Equation
Next, we combine like terms and simplify:
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Distributing the negative sign: x^3 - 3x^2 + 3x - 1 - x^3 - 2x^2 - x = 10x - 5x^2 - 11x - 22
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Combining like terms: -5x^2 + 2x - 1 = -x^2 - x - 22
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Moving all terms to one side: -5x^2 + 2x - 1 + x^2 + x + 22 = 0
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Combining like terms again: -4x^2 + 3x + 21 = 0
Solving the Quadratic Equation
We now have a quadratic equation. There are a couple of ways to solve it:
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Factoring: Try to find two numbers that multiply to give -84 (-4 * 21) and add to give 3. The numbers 12 and -7 work:
- -4x^2 + 12x - 7x + 21 = 0
- 4x(x - 3) - 7(x - 3) = 0
- (4x - 7)(x - 3) = 0
- Therefore, x = 3 or x = 7/4
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Quadratic Formula: If factoring doesn't work easily, use the quadratic formula:
- x = [-b ± √(b^2 - 4ac)] / 2a
- In our case, a = -4, b = 3, and c = 21.
- Plugging these values into the formula and simplifying, we get the same solutions as before: x = 3 or x = 7/4.
Conclusion
The solutions to the equation (x-1)^3 - x(x+1)^2 = 5x(2-x) - 11(x+2) are x = 3 and x = 7/4.