Solving the Equation (x-3)(2x+1) = x(x+5)
This equation involves expanding brackets and rearranging terms to solve for x. Here's how to solve it step-by-step:
1. Expand the brackets:
- On the left-hand side: (x-3)(2x+1) = 2x² + x - 6x - 3 = 2x² - 5x - 3
- On the right-hand side: x(x+5) = x² + 5x
Now the equation becomes: 2x² - 5x - 3 = x² + 5x
2. Rearrange terms to get a standard quadratic equation:
- Subtract x² from both sides: x² - 5x - 3 = 5x
- Subtract 5x from both sides: x² - 10x - 3 = 0
3. Solve the quadratic equation:
This quadratic equation can be solved using the quadratic formula:
- x = [-b ± √(b² - 4ac)] / 2a
Where:
- a = 1 (coefficient of x²)
- b = -10 (coefficient of x)
- c = -3 (constant term)
4. Substitute the values and calculate:
- x = [10 ± √((-10)² - 4 * 1 * -3)] / (2 * 1)
- x = [10 ± √(112)] / 2
- x = [10 ± 4√7] / 2
5. Simplify the solutions:
- x = 5 ± 2√7
Therefore, the solutions to the equation (x-3)(2x+1) = x(x+5) are x = 5 + 2√7 and x = 5 - 2√7.