(x-3)(x-1)=15

2 min read Jun 17, 2024
(x-3)(x-1)=15

Solving the Quadratic Equation: (x-3)(x-1) = 15

This article will guide you through the steps to solve the quadratic equation (x-3)(x-1) = 15.

1. Expanding the Equation

First, we need to expand the left side of the equation by multiplying the two binomials:

(x-3)(x-1) = x² - 4x + 3

Now the equation becomes:

x² - 4x + 3 = 15

2. Rearranging the Equation

Next, we need to rearrange the equation into standard quadratic form (ax² + bx + c = 0):

x² - 4x - 12 = 0

3. Factoring the Equation

Now we can factor the quadratic equation:

(x - 6)(x + 2) = 0

4. Solving for x

To find the solutions for x, we set each factor equal to zero and solve:

  • x - 6 = 0 => x = 6
  • x + 2 = 0 => x = -2

Conclusion

Therefore, the solutions to the quadratic equation (x-3)(x-1) = 15 are x = 6 and x = -2.

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