Factoring and Simplifying the Expression (x-4)^2(x+4)-(x-4)(x+4)^2+3(x^2-16)
This article will guide you through the process of factoring and simplifying the expression (x-4)^2(x+4)-(x-4)(x+4)^2+3(x^2-16).
Recognizing the Pattern
The expression contains repeated terms and the difference of squares pattern. Let's break it down:
- (x-4)^2(x+4): This term has (x-4) as a common factor.
- -(x-4)(x+4)^2: This term also has (x-4) as a common factor.
- 3(x^2-16): This term represents the difference of squares: (x+4)(x-4)
Factoring the Expression
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Factor out the common factor (x-4):
(x-4)^2(x+4) - (x-4)(x+4)^2 + 3(x^2-16) = (x-4)[(x-4)(x+4)-(x+4)^2 + 3(x+4)(x-4)]
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Factor out the common factor (x+4) from the remaining expression:
(x-4)[(x-4)(x+4)-(x+4)^2 + 3(x+4)(x-4)] = (x-4)(x+4)[(x-4)-(x+4) + 3(x-4)]
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Simplify the expression within the brackets:
(x-4)(x+4)[(x-4)-(x+4) + 3(x-4)] = (x-4)(x+4)[3x - 12]
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Factor out the common factor 3 from the last term:
(x-4)(x+4)[3x - 12] = 3(x-4)(x+4)(x-4)
Final Simplified Expression
Therefore, the simplified form of the expression is 3(x-4)^2(x+4).
This process demonstrates how recognizing patterns and factoring can significantly simplify complex algebraic expressions.