(x-4)(x-4i)(x+4i)

3 min read Jun 17, 2024
(x-4)(x-4i)(x+4i)

Factoring and Solving the Polynomial (x-4)(x-4i)(x+4i)

This expression represents a polynomial in factored form. Let's break down what this means and how to solve it.

Understanding the Factors

  • (x-4): This is a simple linear factor, representing a root of the polynomial at x = 4.

  • (x-4i): This factor introduces a complex root at x = 4i, where 'i' is the imaginary unit (√-1).

  • (x+4i): This is the conjugate of the previous factor. It also represents a complex root at x = -4i.

Expanding the Polynomial

To understand the polynomial's behavior, we can expand it by multiplying the factors:

  1. Start with the complex conjugate factors: (x - 4i)(x + 4i) = x² - (4i)² = x² + 16

  2. Multiply the result by the remaining factor: (x² + 16)(x - 4) = x³ - 4x² + 16x - 64

Therefore, the expanded form of the polynomial is x³ - 4x² + 16x - 64.

Key Points

  • Real Root: The polynomial has one real root at x = 4.
  • Complex Roots: The polynomial has two complex roots at x = 4i and x = -4i.
  • Conjugate Pairs: Complex roots always appear in conjugate pairs. This is because the coefficients of the polynomial are real.
  • Symmetry: The graph of this polynomial will exhibit symmetry about the real axis due to the complex conjugate roots.

Conclusion

The expression (x-4)(x-4i)(x+4i) represents a cubic polynomial with one real root and two complex conjugate roots. By expanding the factored form, we can understand the polynomial's behavior and its relationship to the complex number system.

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