(x-5)^2=121

2 min read Jun 17, 2024
(x-5)^2=121

Solving the Equation: (x-5)^2 = 121

This equation involves a squared term, and our goal is to find the values of 'x' that satisfy the equation. Let's break down the steps:

1. Taking the Square Root

First, we need to isolate the term inside the parentheses. To do this, we take the square root of both sides of the equation:

√[(x-5)^2] = ±√121

This gives us:

x - 5 = ±11

2. Solving for x

Now, we have two possible solutions:

  • Case 1: x - 5 = 11 Adding 5 to both sides, we get: x = 16

  • Case 2: x - 5 = -11 Adding 5 to both sides, we get: x = -6

3. The Solutions

Therefore, the solutions to the equation (x-5)^2 = 121 are x = 16 and x = -6.

These solutions represent the two values of 'x' that, when plugged into the original equation, will result in a true statement.

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