(x-5)(x+3)

2 min read Jun 17, 2024
(x-5)(x+3)

Factoring and Expanding: (x-5)(x+3)

This expression represents the multiplication of two binomials: (x-5) and (x+3). Let's explore how to factor and expand it.

Expanding the Expression

To expand the expression, we use the FOIL method:

  • First: Multiply the first terms of each binomial: x * x =
  • Outer: Multiply the outer terms of the binomials: x * 3 = 3x
  • Inner: Multiply the inner terms of the binomials: -5 * x = -5x
  • Last: Multiply the last terms of each binomial: -5 * 3 = -15

Now, combine the terms:

x² + 3x - 5x - 15

Simplify by combining like terms:

x² - 2x - 15

Therefore, the expanded form of (x-5)(x+3) is x² - 2x - 15.

Factoring the Expression

We can also factor the expression x² - 2x - 15 back into its original binomial form. Here's how:

  1. Find two numbers that multiply to -15 and add up to -2. These numbers are -5 and 3.

  2. Rewrite the expression using these numbers: x² - 5x + 3x - 15

  3. Factor by grouping: x(x-5) + 3(x-5)

  4. Factor out the common binomial: (x-5)(x+3)

Therefore, the factored form of x² - 2x - 15 is (x-5)(x+3).

Conclusion

Expanding and factoring are important skills in algebra. By understanding the FOIL method and factoring techniques, you can manipulate expressions like (x-5)(x+3) to reveal their expanded or factored forms.

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