Solving the Quadratic Equation: (x-5)(x+5) - 15x + 75 = 0
This article will guide you through solving the quadratic equation (x-5)(x+5) - 15x + 75 = 0. We'll break down the steps and explain the concepts involved.
1. Expanding the Equation
First, we need to simplify the equation by expanding the product of the binomials:
(x-5)(x+5) = x² - 25
Substituting this back into the original equation:
x² - 25 - 15x + 75 = 0
2. Combining Like Terms
Next, combine the constant terms:
x² - 15x + 50 = 0
3. Factoring the Quadratic Equation
Now, we factor the quadratic expression. We need to find two numbers that add up to -15 (the coefficient of the x term) and multiply to 50 (the constant term). These numbers are -10 and -5.
Therefore, we can factor the equation as:
(x - 10)(x - 5) = 0
4. Solving for x
To find the solutions, we set each factor equal to zero:
x - 10 = 0 or x - 5 = 0
Solving for x in each case:
x = 10 or x = 5
5. The Solutions
Therefore, the solutions to the quadratic equation (x-5)(x+5) - 15x + 75 = 0 are:
x = 10 and x = 5
This means that the equation is satisfied when x is equal to either 10 or 5.