Solving the Quadratic Equation: (x-5)(x-6) = 2
This article will guide you through solving the quadratic equation (x-5)(x-6) = 2. We will explore the steps involved in finding the solutions for x.
Expanding the Equation
First, we need to expand the left side of the equation by multiplying the binomials:
(x-5)(x-6) = 2
x² - 11x + 30 = 2
Rearranging the Equation
To solve for x, we need to set the equation to zero:
x² - 11x + 28 = 0
Factoring the Equation
Now, we factor the quadratic expression:
(x-4)(x-7) = 0
Finding the Solutions
For the product of two factors to be zero, at least one of the factors must be zero. Therefore, we have two possible solutions:
- x - 4 = 0 => x = 4
- x - 7 = 0 => x = 7
Conclusion
The solutions to the quadratic equation (x-5)(x-6) = 2 are x = 4 and x = 7. These values, when substituted into the original equation, will make the equation true.