(x-7)(x+3)=24

2 min read Jun 17, 2024
(x-7)(x+3)=24

Solving the Equation: (x-7)(x+3) = 24

This equation involves a product of two binomials equaling a constant. To solve it, we need to follow these steps:

1. Expand the Left Side

First, we need to expand the left side of the equation using the distributive property (or FOIL method):

(x-7)(x+3) = x² + 3x - 7x - 21 = x² - 4x - 21

Now our equation becomes: x² - 4x - 21 = 24

2. Move the Constant to the Left Side

To solve this quadratic equation, we need to set it equal to zero. We can do this by subtracting 24 from both sides:

x² - 4x - 45 = 0

3. Factor the Quadratic Expression

Now we need to factor the quadratic expression on the left side:

(x - 9)(x + 5) = 0

4. Solve for x

For the product of two factors to equal zero, at least one of the factors must be zero. Therefore:

  • x - 9 = 0 => x = 9
  • x + 5 = 0 => x = -5

Solution

The solutions to the equation (x-7)(x+3) = 24 are x = 9 and x = -5.

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