Understanding the Differential Equation (x-h)^2 + (y-k)^2 = r^2
The equation (x-h)^2 + (y-k)^2 = r^2 represents the standard form of a circle with center (h, k) and radius r. While it may not appear to be a differential equation, we can derive a differential equation from it by representing the equation in terms of its first derivative.
Derivation of the Differential Equation
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Implicit Differentiation: We differentiate both sides of the equation with respect to x, treating y as a function of x.
2(x-h) + 2(y-k) * y' = 0
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Solving for y': We solve the equation for y' to get the differential equation.
y' = - (x-h) / (y-k)
This equation relates the derivative of y with respect to x (y') to the coordinates of the circle's center (h, k) and the x and y coordinates of the point on the circle.
Significance of the Differential Equation
The differential equation obtained from the circle's equation has significant implications in understanding and analyzing circles.
- Geometric Interpretation: It connects the slope of the tangent line to the circle at a point (x, y) to the coordinates of the circle's center and the point itself.
- Applications: This differential equation finds applications in various fields, including:
- Physics: Analyzing motion along circular paths.
- Engineering: Designing circular structures.
- Computer Graphics: Generating and manipulating circular shapes.
Example: Finding the Tangent Line
Let's consider the circle with the equation (x-1)^2 + (y-2)^2 = 9. We can find the equation of the tangent line at the point (4, 5) by following these steps:
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Find the slope of the tangent line: Using the differential equation, we get:
y' = - (x-1) / (y-2)
Substitute (x, y) = (4, 5) into the equation:
y' = - (4-1) / (5-2) = -1
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Use the point-slope form of the equation: The equation of the tangent line is:
y - 5 = -1(x - 4)
Simplifying, we get the equation of the tangent line:
y = -x + 9
Conclusion
The differential equation derived from the circle's equation provides a powerful tool for understanding and manipulating circular shapes. By connecting the derivative of y with respect to x to the coordinates of the circle's center and a point on the circle, it opens up various applications in different fields.