(x-yi)(2+3i)=(x-2i)/(1-i)

3 min read Jun 17, 2024
(x-yi)(2+3i)=(x-2i)/(1-i)

Solving Complex Equation: (x - yi)(2 + 3i) = (x - 2i) / (1 - i)

This article will guide you through the process of solving the complex equation: (x - yi)(2 + 3i) = (x - 2i) / (1 - i). We will utilize the properties of complex numbers and algebraic manipulation to find the values of x and y.

Expanding and Simplifying

  1. Expand the left side of the equation: (x - yi)(2 + 3i) = 2x + 3xi - 2yi - 3yi² = (2x + 3y) + (3x - 2y)i
    Remember that i² = -1.

  2. Rationalize the denominator on the right side: (x - 2i) / (1 - i) = [(x - 2i)(1 + i)] / [(1 - i)(1 + i)] = (x + xi - 2i - 2i²) / (1 - i²) = (x + 2) + (x - 2)i

Equating Real and Imaginary Parts

Now we have the equation: (2x + 3y) + (3x - 2y)i = (x + 2) + (x - 2)i. For two complex numbers to be equal, their real and imaginary parts must be equal. This gives us two equations:

  • Real Part: 2x + 3y = x + 2
  • Imaginary Part: 3x - 2y = x - 2

Solving the System of Equations

We now have a system of two linear equations with two unknowns. We can solve for x and y using various methods such as substitution or elimination.

Using Elimination:

  1. Rearrange the equations:

    • x - 3y = 2
    • 2x - 2y = -2
  2. Multiply the first equation by -2:

    • -2x + 6y = -4
    • 2x - 2y = -2
  3. Add the two equations together:

    • 4y = -6
  4. Solve for y:

    • y = -3/2
  5. Substitute the value of y back into either original equation to solve for x:

    • x - 3(-3/2) = 2
    • x + 9/2 = 2
    • x = -5/2

Solution

Therefore, the solution to the complex equation (x - yi)(2 + 3i) = (x - 2i) / (1 - i) is x = -5/2 and y = -3/2. This means the complex number is (-5/2 + 3/2i).

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